Lioville's Theorem In Complex Analysis | Mathquery
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Lioville's Theorem :- Statement : If a function f(z) is analytic for all limit values of z and is bounded then f(z) is constant . Proof : Let z₁ , z₂ be any two point of the z-plane the contour C to be a large circle of radius R centred at origin and containing the point z₁ , z₂ . Therefore |r₁|<R and |z₂|<R . Also as f(z) is bounded therefore ∃ a positive M such that f|(z)|≤M for all z. By Cauchy's Integral formula we have f(z₁) = 1/2πi ∫ f(z) dz /z-z₁ c f(z₂) = 1/2πi ∫ f(z) dz /z-z₂ c ∴ f(z₁) - f(z₂) = 1/2πi ∫ f(z) dz /z-z₁ c - 1/2πi ∫ f(z) dz /z-z₂ c = 1/2πi ∫ (z₁-z₂) f(z) dz /(z-z₁)(z-z₂) c |f(z₁)-f(z₂)| = |1/2πi ∫(z₁-z₂)f(z) dz /(z-z₁)(z-z₂)|