The Lagrange Differential Equation With Scientist Name
Hello my friends,
I want discuss something about the famous equation called LAGRANGE EQUATION.
This equation is used to solve differential equations of higher degree like CLAIRAUT EQUATION.
Now ,
The equation y= xg(p)+ f(p) is associated with the name of JOSEPH LOUIS LAGRANGE (1736_1813).
This is a generalised form of CLAIRAUT's EQUATION.
If we put g(p) =p, it is in CLAIRAUT's form.
Differentiating w.r.t x and putting dy/ dy/dx = y'= p, we have
p= g(p) + xg'(p) dp/dx+f'(p) dp/dx
or [p-g(p)] dx/dp= xg'(p)+ f'(p)
or dx/dp= g'(p)x/p-g(p) + f'(p)/p-g(p)..(1)
The equation (1) is a linear differential equation in x and dx/dp and it is integrable using different types of methods.
Solve y= 2xy- p^3
Differentiating,
we get
p= 2p+ 2xdp/dx - 3p^2 dp/dx
or p=(-2x+3p^2)dp/dx
=> dx/dp + 2x/p=3p
I.F. = e^∫2/pdp=e^logp^2 = p^2
Multiplying both sides of equation by p^2,
we obtain
d/dp(xp^2)=3p^3,
Which on integration yields
xp^2=3/4p^4+c
i.e. x= c/p^2+3/4p^2.
Thus, the general solution is the elimination of p between y= 2xp- p^3
and x=c/p^2 + 3/4p^2
ABOUT SCIENTIST:
Joseph-Louis Lagrange was an Italian Enlightenment Era mathematician and astronomer.
He made significant contributions to the fields of analysis, number theory, and both classical and celestial mechanics.
I want discuss something about the famous equation called LAGRANGE EQUATION.
This equation is used to solve differential equations of higher degree like CLAIRAUT EQUATION.
Now ,
The equation y= xg(p)+ f(p) is associated with the name of JOSEPH LOUIS LAGRANGE (1736_1813).
This is a generalised form of CLAIRAUT's EQUATION.
If we put g(p) =p, it is in CLAIRAUT's form.
Differentiating w.r.t x and putting dy/ dy/dx = y'= p, we have
p= g(p) + xg'(p) dp/dx+f'(p) dp/dx
or [p-g(p)] dx/dp= xg'(p)+ f'(p)
or dx/dp= g'(p)x/p-g(p) + f'(p)/p-g(p)..(1)
The equation (1) is a linear differential equation in x and dx/dp and it is integrable using different types of methods.
Example:
Solve y= 2xy- p^3
Solution.
Differentiating,
we get
p= 2p+ 2xdp/dx - 3p^2 dp/dx
or p=(-2x+3p^2)dp/dx
=> dx/dp + 2x/p=3p
I.F. = e^∫2/pdp=e^logp^2 = p^2
Multiplying both sides of equation by p^2,
we obtain
d/dp(xp^2)=3p^3,
Which on integration yields
xp^2=3/4p^4+c
i.e. x= c/p^2+3/4p^2.
Thus, the general solution is the elimination of p between y= 2xp- p^3
and x=c/p^2 + 3/4p^2
ABOUT SCIENTIST:
Joseph-Louis Lagrange was an Italian Enlightenment Era mathematician and astronomer.
He made significant contributions to the fields of analysis, number theory, and both classical and celestial mechanics.
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