Power Series And It's Theorems
Power Series And It's Theorems :
Definition Of Power Series :
A series of the form
∞
Σ aₙ(x-x₀)ⁿ = a₀+a₁(x-x₀)+a₂(x-x₀)²+......
n=0
+ aₙ(x-x₀)ⁿ+....
is called a power series .
where x is a continuous variable and the constants aₙ,x₀ are real and independent of x .
Remarks :
--> If we change the variable x= t+x₀ , then the power series reduces to
∞
Σ aₙ tⁿ .
n=0
-->For x=0 , every power series is convergent , whatever the value of co_efficients .
--> A power series is either
(1) convergent for no value of x other than x= 0 , then it is said to be nowhere convergent .
(2) convergent for all values of x and is called everywhere convergent .
(3) convergent for some values of x and diverges for others .
--> The totality of point x for which a power series converges is called Region Of Convergence .
Theorem _ 1 :
∞
If a power series Σ aₙ xⁿ converges
n=0
for a particular value x₀ of x then it converges absolutely for all values of x for which |x| < |x₀|.
Proof :
Let the series Σ aₙ x₀ⁿ converges .
Then nth term of the given series aₙx₀ⁿ must tends to 0 as n-->∞ . Therefore , we can find a number M>0 such that
|aₙx₀ⁿ|≤M for all n .
Then |aₙxⁿ|≤M|x/x₀|ⁿ .........(1)
Now , since |x|<|x₀| , then geometric series Σ|x/x₀|ⁿ converges .
Hence
from(1), the series Σ|aₙxⁿ| converges for all values of x for which |x| < |x₀| .
Theorem _2 :
The power series Σ aₙ xⁿ either
(i) converges absolutely for all x .
or (ii) converges for x= 0 only .
or (iii) ∃ R > 0 such that the series converges absolutely , when |x| < R and diverges when |x|>R .
Proof :
Let x∈ + and P be the set of all x for which the given power series Σ aₙxⁿ converges . Then given series is definitely converges to 0 .
∴ 0 ∈ P .
Then P may or may not contain numbers other than 0 . If x₀ ∈ P then by previous theorem , every x with 0≤x≤x₀ is also in P .
If for all non_ negative real numbers are in P , then Σ aₙ xⁿ absolutely converges for all x .
On the other hand , if P does not contain all non_negative numbers , then it has a least upper bound R (R>0) . Let R>0 and |x₀|< R .
Then , to show that Σ aₙ x₀ⁿ absolutely converges .
Let us choose R₀ such that |x₀|<R₀<R . Then R₀∈ P and so the series converges for x= R₀ . Then by previous theorem
Σ |aₙx₀ⁿ | converges .
Finally , we prove if |x'|>R≥0 , the series can't converges for x= x' .
Select R₀ with R<R₀<|x'| . If Σaₙx'ⁿ were to converge , then by previous theorem Σ aₙR₀ⁿ also converges , which contradicts the fact R= P .
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